8-8
T(t) = T0 +  R(t)dt + e(t) = T0 + (R0t + 1/2At2 + …) +   Ei(t)dt +e(t)
Where,
   T(t) = time difference between two clocks at time t after synchronization
   T0 = synchronization error at t = 0
   R(t) = the rate (i.e., fractional frequency) difference between the two clocks
             under comparison; R(t) = R0 + At + …Ei(t)
   e(t) = error due to random fluctuations = tsy(t)
   R0 = R(t) at t = 0
   A = aging term (higher order terms are included if the aging is not linear)
   Ei(t) = rate difference due to environmental effects (temperature, etc.)
- - - - - - - - - - - - - -
Example:  If a watch is set to within 0.5 seconds of a time tone (T0 = 0.5 s), and the
watch initially gains 2 s/week (R0 = 2 s/week), and the watch rate ages -0.1 s per
week2, (A = -0.1 s/week2), then after 10 weeks (and assuming Ei(t) = 0):
T (10 weeks)  = 0.5 (2 x 10) + 1/2(-0.1 x (10)2) = 15.5 seconds.  
Clock Errors
   No clock can ever keep perfect time because all oscillators exhibit random and systematic errors (as discussed in chapters 4 and 6), clocks cannot be set perfectly (e.g., due to noise), and time is a function of position and motion (relativistic effects are discussed later in this chapter).